本文关键词:Java 8, 函数式接口,lambda 。
介绍
全路径: java.util.function.Function 。
Java 8 中引入。
源码:
/**
* Represents a function that accepts one argument and produces a result.
*
* <p>This is a <a href="package-summary.html">functional interface</a>
* whose functional method is {@link #apply(Object)}.
*
* @param <T> the type of the input to the function
* @param <R> the type of the result of the function
*
* @since 1.8
*/
@FunctionalInterface
public interface Function<T, R> {
/**
* Applies this function to the given argument.
*
* @param t the function argument
* @return the function result
*/
R apply(T t);
/**
* Returns a composed function that first applies the {@code before}
* function to its input, and then applies this function to the result.
* If evaluation of either function throws an exception, it is relayed to
* the caller of the composed function.
*
* @param <V> the type of input to the {@code before} function, and to the
* composed function
* @param before the function to apply before this function is applied
* @return a composed function that first applies the {@code before}
* function and then applies this function
* @throws NullPointerException if before is null
*
* @see #andThen(Function)
*/
default <V> Function<V, R> compose(Function<? super V, ? extends T> before) {
Objects.requireNonNull(before);
return (V v) -> apply(before.apply(v));
}
/**
* Returns a composed function that first applies this function to
* its input, and then applies the {@code after} function to the result.
* If evaluation of either function throws an exception, it is relayed to
* the caller of the composed function.
*
* @param <V> the type of output of the {@code after} function, and of the
* composed function
* @param after the function to apply after this function is applied
* @return a composed function that first applies this function and then
* applies the {@code after} function
* @throws NullPointerException if after is null
*
* @see #compose(Function)
*/
default <V> Function<T, V> andThen(Function<? super R, ? extends V> after) {
Objects.requireNonNull(after);
return (T t) -> after.apply(apply(t));
}
/**
* Returns a function that always returns its input argument.
*
* @param <T> the type of the input and output objects to the function
* @return a function that always returns its input argument
*/
static <T> Function<T, T> identity() {
return t -> t;
}
}
示例
代码示例1
import java.util.function.Function;
public class Main {
public static void main(String[] args) {
Function<Long, String> function = aLong -> {
return "数字是: " + aLong;
};
String result = function.apply(123L);
System.out.println(result);
}
}
执行结果:
数字是: 123
代码示例2
import java.util.function.Function;
public class Main {
public static void main(String[] args) {
Function<Long, Long> function = aLong -> {
System.out.println("数字加2");
return aLong + 2;
};
Function<Long, Long> function2 = function.compose(aLong -> {
System.out.println("数字加10");
return aLong + 10;
});
Function<Long, Long> function3 = function2.andThen(aLong -> {
System.out.println("数字加100");
return aLong + 100;
});
Long result = function3.apply(123L);
System.out.println("执行结果: " + result);
}
}
执行结果:
数字加10
数字加2
数字加100
执行结果: 235